1868 Rhode Island gubernatorial election

Rhode Island gubernatorial election
1868 Rhode Island gubernatorial election

← 1867 1 April 1868 1869 →
 
Nominee Ambrose Burnside Lyman Pierce
Party Republican Democratic
Popular vote 10,038 3,390
Percentage 74.69% 25.23%

Governor before election

Ambrose Burnside
Republican

Elected Governor

Ambrose Burnside
Republican

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The 1868 Rhode Island gubernatorial election was held on 1 April 1868 in order to elect the Governor of Rhode Island. Incumbent Republican Governor Ambrose Burnside won re-election against Democratic nominee Lyman Pierce in a rematch of the 1866 and 1867 election.[1]

General election

On election day, 1 April 1868, incumbent Republican Governor Ambrose Burnside won re-election by a margin of 6,648 votes against his opponent Democratic nominee Lyman Pierce, thereby retaining Republican control over the office of Governor. Burnside was sworn in for his third term on 4 May 1868.[2]

Results

Rhode Island gubernatorial election, 1868
Party Candidate Votes %
Republican Ambrose Burnside (incumbent) 10,038 74.69
Democratic Lyman Pierce 3,390 25.23
Scattering 11 0.08
Total votes 13,439 100.00
Republican hold

References

  1. ^ "Ambrose Burnside". National Governors Association. Retrieved 7 April 2024.
  2. ^ "RI Governor". ourcampaigns.com. 26 July 2005. Retrieved 7 April 2024.