Gosławice, Kuyavian-Pomeranian Voivodeship

Village in Kuyavian-Pomeranian Voivodeship, Poland
52°45′N 18°41′E / 52.750°N 18.683°E / 52.750; 18.683Country PolandVoivodeshipKuyavian-PomeranianCountyAleksandrówGminaZakrzewo

Gosławice [ɡɔswaˈvit͡sɛ] is a village in the administrative district of Gmina Zakrzewo, within Aleksandrów County, Kuyavian-Pomeranian Voivodeship, in north-central Poland.[1] It lies approximately 5 kilometres (3 mi) east of Zakrzewo, 13 km (8 mi) south of Aleksandrów Kujawski, and 32 km (20 mi) south of Toruń.

References

  1. ^ "Central Statistical Office (GUS) - TERYT (National Register of Territorial Land Apportionment Journal)" (in Polish). 2008-06-01.
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